a triangle has a side 2x , 3y and 4z. if x=2y=3z=12. find the perimeter of triangle..

Question

please solve this alzebric equation..

Answer 1

x = 2y= 3z= 12.  So:

 

x = 12

2y = 12 so y = 6

3z = 12 so z = 4

 

Now you know the values of x, y, and z, so plug them into the given perimeter equation to get the answer.

 

Perimeter = 2x + 3y + 4z = ______?