Bryce O.
asked 03/13/14can you please factor out -12x^5+4x^4+4x^2
I need it as fast as possible
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2 Answers By Expert Tutors
Steve S. answered 03/13/14
Tutor
5
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Tutoring in Precalculus, Trig, and Differential Calculus
If the problem were to factor g(x) = –15x^6 + 5x^4 + 3x^2:
g(x) = –15x^6 + 6x^4 + 3x^2
g(x) = –3x^2(5x^4 – 2x^2 – 1)
h(x) = 5x^4 – 2x^2 – 1
h(x) = 5(x^2)^2 – 2(x^2) – 1
x^2 = (- -2 ± √(4-4(-5)) )/(2*5)
x^2 = (2 ± 2√(1+5) )/(2*5)
x^2 = (1 ± √(6) )/5
x = ± √( (1 ± √(6) )/5 )
g(x) = –3x^2(x ± √( (1 ± √(6) )/5 ) )
g(x) =
–3x^2
* (x – √( (1 + √(6) )/5 ) )
* (x + √( (1 + √(6) )/5 ) )
* (x – √( (1 – √(6) )/5 ) )
* (x + √( (1 – √(6) )/5 ) )
g(x) = –15x^6 + 6x^4 + 3x^2
g(x) = –3x^2(5x^4 – 2x^2 – 1)
h(x) = 5x^4 – 2x^2 – 1
h(x) = 5(x^2)^2 – 2(x^2) – 1
x^2 = (- -2 ± √(4-4(-5)) )/(2*5)
x^2 = (2 ± 2√(1+5) )/(2*5)
x^2 = (1 ± √(6) )/5
x = ± √( (1 ± √(6) )/5 )
g(x) = –3x^2(x ± √( (1 ± √(6) )/5 ) )
g(x) =
–3x^2
* (x – √( (1 + √(6) )/5 ) )
* (x + √( (1 + √(6) )/5 ) )
* (x – √( (1 – √(6) )/5 ) )
* (x + √( (1 – √(6) )/5 ) )
Cameron C. answered 03/13/14
Tutor
5.0
(340)
Parent Recommended Math, Science, and Reading Tutor
notice that what each term has in common is a factor of 4x2
so you get 4x2(-3x3 + x2 + 1)
you can check it by distributing the 4x2 back into the (-3x3 + x2 + 1)
another way of looking at it, if it helps, is once you realize that each term has a 4x2 as a factor, then you divide each term by 4x2 which is how you then get the other factor of (-3x3 + x2 + 1)
Vivian L.
Hi Cameron;
I agree with your answer. My guess is that the parenthetical expression must be factored again. This is why I asked Bryce if he copied this exactly right.
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03/13/14
Cameron C.
I see what you mean. Its difficult sometimes because the questions asked on here don't give all the context in which they are being asked.
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03/13/14
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Vivian L.
03/13/14