Riley M.

asked • 03/15/17

Expected Value

You wager $1 on the roll of three die, any doubles wins $2, any triples wins $3, and anything else loses. Find the expected value of this wager.

1 Expert Answer

By:

Gene G. answered • 03/15/17

Tutor
5.0 (257)

You can do it! I'll show you how.

Riley M.

Wouldn't the additional probability of a double be 5/18, since you took 1/3*5/6?
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03/15/17

Riley M.

And for the net return, how does 20/18=5/9?
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03/15/17

Gene G.

Oops!  You're right.  Thanks for catching my goof!
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03/15/17

Riley M.

So with that in mind how would it change the final answer?
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03/15/17

Riley M.

I am still confused on how to get the net return
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03/15/17

Gene G.

You're right again.
I was really focused on how to combine things and I loused up the simple arithmetic!
I found a typo in the triple probability and more errors.  
I'll pick it up here:
The additional probability of a double is 1/3 * 5/6 = 5/18
Net probability of a double is 1/6 + 5/18 = 8/18 = 4/9
That would return 2 * 4/9 = 8/9 on average.
Net probability of a triple was 1/36. That would return 3 * 1/36 = 1/12 on average.
Net return would be 8/9 + 1/12 = 32/36 + 3/36 = 35/36 = 0.97 on average.
On average, a $1 bet would return $0.97.
Turns out to be more like real casino odds.  Just a little in favor of the house.
 
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03/15/17

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