Andrew and Barry eat 16 pieces of chocolate. Barry eats 6 more than 4 times as many chocolates as Andrew. How many chocolates do they each eat

Question

Andrew and Barry eat 16 pieces of chocolate. Barry eats 6 more than 4 times as many chocolates as Andrew. How many chocolates do they each eat

Answer 1

Let, Andrew eats x chocolate

So, Barry eats (4x+6) chocolate [According to the given condition]

The equation to solve the problem is

x+(4x+6) = 16

5x+6 = 16

5x = 10 [Subtract 6 from both sides]

x = 2 [Divide both sides by 5]

Hence, Andrew eats 2 chocolates and Barry eats (4x+6) = (4*2+6) = (8+6) = 14 chocolates.

    

Answer 2

if x = # eaten by Andrew, then Barry ingests 4x + 6.

Total 16 = x + (4x + 6)

16 = 5x + 6

10 = 5x

x = 2

Andrew: 2

Barry: 14