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Andrew and Barry eat 16 pieces of chocolate. Barry eats 6 more than 4 times as many chocolates as Andrew. How many chocolates do they each eat

Andrew and Barry eat 16 pieces of chocolate. Barry eats 6 more than 4 times as many chocolates as Andrew. How many chocolates do they each eat
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1 Answer

Let, Andrew eats x chocolate
So, Barry eats (4x+6) chocolate [According to the given condition]
The equation to solve the problem is
x+(4x+6) = 16
5x+6 = 16
5x = 10 [Subtract 6 from both sides]
x = 2 [Divide both sides by 5]
Hence, Andrew eats 2 chocolates and Barry eats (4x+6) = (4*2+6) = (8+6) = 14 chocolates.