Michael F. answered • 02/15/14

Mathematics Tutor

Freedom G.

asked • 02/15/14what is the equation of the line that passes through the points (0,3) (2,0)?

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Michael F. answered • 02/15/14

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Mathematics Tutor

What about the double intercept form x/2+y/3=1?

Timothy P. answered • 02/15/14

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New to Wyzant
Tim (Physics, Math, and Engineering)

Another version you can use is slope-intercept form. The two above are standard and point-slope forms.

First you do need to find the slope of the line based on

m=(y2-y1)/(x2-x1)

so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)

x1=0

y1=3

x2=2

y2=0

m= (0-3)/(2-0) = -3/2

Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0)

Due to have the x=0 point, you are pretty much done:

y=-3/2*x+3

If you do not have a (0,y) form, you can solve as follows:

Write out the formula with your slope value inserted:

y=-3/2*x+b

Choose one of your points on your line to solve for b. I choose (2,0):

0=-3/2*2+b

0=-3*1+b

3=b --> b=3

Vivian L. answered • 02/15/14

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Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH

Hi Freedom;

(0,3) (2,0)

Slope is change-of-y divided by change-of-x...

m=(y-y_{1})/(x-x_{1})

m=(3-0)/(0-2)

m=3/-2=-3/2

Slope-intercept format is...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

y=(-3/2)x+b

The y intercept is provided as (0,3)...

y=(-3/2)x+3

The slope of the line,m=y-y_{1}/x-x_{1}

m=3-0/0-2=-3/2

The point slope form is

y-y_{1}=m(x-x_{1})

y-0=-3/2(x-2)

y=-3/2(x-2)

2y=-3x+6

3x+2y=6

Steve S. answered • 02/15/14

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Tutoring in Precalculus, Trig, and Differential Calculus

(0,3) & (2,0) are the y and x intercepts,

so the intercept form is x/2 + y/3 = 1.

Multiply both sides by 6:

3x + 2y = 6.

See GeoGebra graph here:

http://www.wyzant.com/resources/files/261743/intercept_form

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Steve S.

02/15/14