what is the equation of the line that passes through the points (0,3) (2,0)?

Question

what is the equation  of the line that passes through the points (0,3) (2,0)?

Answer 1

What about the double intercept form x/2+y/3=1?

Answer 2

Another version you can use is slope-intercept form.   The two above are standard and point-slope forms.

 

First you do need to find the slope of the line based on 

m=(y2-y1)/(x2-x1)

 

so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)

x1=0

y1=3

x2=2

y2=0

 

m= (0-3)/(2-0) = -3/2

 

Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0)  

Due to have the x=0 point, you are pretty much done:

 

y=-3/2*x+3

 

If you do not have a (0,y) form, you can solve as follows:

Write out the formula with your slope value inserted:

y=-3/2*x+b

 

Choose one of your points on your line to solve for b.  I choose (2,0):

0=-3/2*2+b

0=-3*1+b

3=b --> b=3

 

 

 

Answer 3

Hi Freedom;

(0,3) (2,0)

Slope is change-of-y divided by change-of-x...

m=(y-y₁)/(x-x₁)

m=(3-0)/(0-2)

m=3/-2=-3/2

Slope-intercept format is...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

y=(-3/2)x+b

The y intercept is provided as (0,3)...

y=(-3/2)x+3

 

Answer 4

 

 

The slope of the line,m=y-y₁/x-x₁

                             m=3-0/0-2=-3/2

 

The point slope form is

 

y-y₁=m(x-x₁)

 

y-0=-3/2(x-2)

 

y=-3/2(x-2)

 

2y=-3x+6

 

3x+2y=6

Answer 5

(0,3) & (2,0) are the y and x intercepts,

 

so the intercept form is x/2 + y/3 = 1.

 

Multiply both sides by 6:

 

3x + 2y = 6.

 

See GeoGebra graph here:

http://www.wyzant.com/resources/files/261743/intercept_form