
David W. answered 05/16/16
Tutor
4.7
(90)
Experienced Prof
Let x = number of cards
Company A charges: $0.15x
Company B charges: $10.00 + $0.10x
For company B to be the cheaper option: ( B < A )
$10.00 + $0.10x < $0.15x
$10.00 < $0.05x [subtracting positive from both sides
retains the sense of the inequality and x is positive]
200 < x [dividing by positive 0.05 retains sense of inequality]
x > 200 [read in reverse to make sense]
You would have to buy more than 200 cards for B to be cheaper.
Let's check:
For 200 cards,
Is $10.00 + $0.10(200) < $0.15(200) ?
$10.00 + $20.00 < $30.00 ?
$30.00 < $30.00 ?no, they are equal
For 201 cards,
Is $10.00 + $0.10(201) < $0.15(201) ?
$10.00 + $20.10 < $30.15 ?
$30.10 < $30.15 ?yes