
Kenneth S. answered 03/28/16
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The definite integral of a PDF over its domain [2,3] must be 1.
So you require that ∫23(3/k)x4dx = 1 ...I'm assuming that the 4th power of x is a factor in the integrand.
Antiderivative F(x) = (3x5)/(5k) and you need to have F(3) - F(2) = 1 ... (evaluating definite integral on [2,3])