what force (N) would the window have to withstand?

Question

A medium-sized beer company which recently hired you is experimenting with extremely long, vertical tanks for storing freshly fermented product. As fate would have it, on your first day of work you accidentally drop your lunch box into one of the tanks. The open tank is 150 m high with a diameter of 3.5 m, and is full of beer at approximately 0.4C. Fortunately, the company diving suit is available. The viewing window in the suite has an
area of roughly 65 cm2. If the pressure on the inside of the suit was maintained at 1.0 atm, what force (N) would the window have to withstand if you had to dive all the way to the bottom of the tank to retrieve your lunch? Assume the specific gravity of cold beer is 1.05

Answer 1

You will need to find the following:

1. the mass of the beer (volume times specific gravity times density of water, in kg)
2. the weight of the beer (in N)
3. the pressure due to the beer at the bottom (weight divided by area of bottom, in Pa = N/m²)
4. the inward force on the viewing window due to the beer (pressure times area, in N)
5. the outward force on the viewing window due to the air inside the suit
6. the net force

I hope this helps. Go Beavs!

Answer 2

Hey N -- our dive takes us 500ft underwater ... 1atm is about 30ft of water or 15psi ...

the dive mask will be facing about 15-16atm or nearly 250psi ...

65cm^2 (inch/2.5cm)^2 ==> about 10 sq.in. mask window facing 250 lbf/sq.in. 

==> there's 2500 lbf pressing in on the mask window ... a good TON of force!  Regards :)