Philip P. answered • 01/28/16
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Use the formula for the impulse, a force applied for a given amount of time:
F*Δt = m*Δv
where:
- F = the force = 600 N
- Δt = the time the force is applied to the ball (aka foot is in contact w/ball) = unknown
- m = mass of the ball = 430 g = 0.43 kg (watch your units!!!)
- Δv = the change in velocity of the ball = 15 m/s - 0 m/s = 15 m/s
Let's plug in the numbers we have and solve for Δt:
F*Δt = m*Δv
(600 N)*Δt = (0.43 kg)(15 m/s)
600*Δt = 6.45
Δt = 6.45/600
Δt = 0.01075 s
Micah S.
You did not factor the (unknowns) internal pressure of the ball or its coefficient of restitution. A ball with PSI 8 vs. PSI 12 are going to allow for different deformations and elastic rebound. It's a hollow, pressurized sphere, not billiards. The foot may still be in contact with the ball for a few milliseconds after impulse has been transferred.12/04/22