Arthur D. answered 11/14/15
Tutor
5.0
(270)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
85=219.37e^(-0.155x)
85/219.37=e^(-0.155x)
0.3874732=e^(-0.155x)
take the natural log of both sides
ln(0.3874732)=ln(e^[-0.155x])
-0.94810859387=-0.155x because ln(e^[x])=x
-0.94810859387/-0.155=x
x=6.1168296 (round off accordingly)