ROGER F. answered 07/19/15
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DR ROGER - TUTOR OF MATH, PHYSICS AND CHEMISTRY
x3 + 64 = 0 can be written as x3 + 43 = 0, which is the sum of two cubes. [ a3 + b3 = (a + b)(a2 - ab + b2) ]
This factors into (x + 4)(x2 - 4x + 16) = 0
So x = -4 or (solving x2 - 4x + 16 = 0 using the quadratic formula, or by completing the square) x = 2±2i√3
x cannot = 4, so the answer is c