Inactive Tutor answered 08/21/23
3a +4c = 98
2a +3c = 69
8a +12c =4(69)
9a +12c = 3(98)
a = -4(69)+3(98)
a = -276+294
a= 18 adults
c = (98-3(18))/4 = (98-54)/4 = 44/4 = 11 children
2(18)+3(11)= 36+33 = 69
3(18)+4(11) =54+44 = 98
Brian S.
asked 05/04/21Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay 98 dollars wo adults and three children must pay 69 dollars Find the price of the adult's ticket and the price of a child's ticket.
Inactive Tutor answered 08/21/23
3a +4c = 98
2a +3c = 69
8a +12c =4(69)
9a +12c = 3(98)
a = -4(69)+3(98)
a = -276+294
a= 18 adults
c = (98-3(18))/4 = (98-54)/4 = 44/4 = 11 children
2(18)+3(11)= 36+33 = 69
3(18)+4(11) =54+44 = 98
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