Michael J. answered 03/01/15
Tutor
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Great at Simplifying Complex Concepts and Processes
We will use the same substitution and elimination method when working with two variables.
x + y + z = 73 eq1
-2x + 5y = 80 eq2
x - z = -9 eq3
First, we will solve for z from eq3.
-z = -9 - x
z = x + 9
Substitute this value of z into eq1.
x + y + z = 73
x + y + (x + 9) = 73
x + y + x + 9 = 73
2x + y = 64
Now we will work with new eq1 and original eq2.
2x + y = 64
-2x + 5y = 80
Lets go on ahead and add these two equations to eliminate the x terms.
6y = 144
y = 24
Substitute this y value into eq2.
-2x + 5y = 80
-2x + 5(24) = 80
-2x + 120 = 80
-2x = -40
x = 20
Substitute this x value into eq3.
z = x + 9
z = 20 + 9
z = 29
Your solutions are
x = 20
y = 24
z = 29