Area = (1/2)∫(from 0 to π/2) r2dθ = (1/2)∫(from 0 to π/2) sin2(2θ)dθ = (1/2)∫(from 0 to π/2) (1 - cos(4θ))/2 dθ =
(1/4) [θ - (1/4)sin(4θ)](from 0 to π/2) = π/8 ≈ 0.393 (using the "pi" key on the calculator)
Stephanie B.
asked 11/12/20Find the area enclosed by r = sin 2θ for .Type your answer in the space below and give 3 decimal places. If your answer is less than 1, place a leading "0" before the decimal point
My answer: 0.392
Area = (1/2)∫(from 0 to π/2) r2dθ = (1/2)∫(from 0 to π/2) sin2(2θ)dθ = (1/2)∫(from 0 to π/2) (1 - cos(4θ))/2 dθ =
(1/4) [θ - (1/4)sin(4θ)](from 0 to π/2) = π/8 ≈ 0.393 (using the "pi" key on the calculator)
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