
Giorgio C. answered 11/10/20
PhD Aerospace Engineering: Algebra, Calculus, Matlab, Geometry,Italian
Given the position vector , the vector tangent to the path is given by the derivative with respect to the parameter "t" of the position vector: (-2sin t, 4cost). The tangent vector is horizontal when 4*cos(t) = 0, i.e. when t = pi/2 and 3/2*pi.