
Conrad D. answered 11/07/20
Engineering and Math tutor
A1 - A2 = ∫ π ( 1/2 r1 ^ 2 —1/2 r 2 ^ 2 ) dθ
0
= ∫ π 1/2 [ ( 1 ^ 2 − ( 1 − sin θ ) ^ 2 ] dθ
0
= - 1/2 ∫ π ( 2 sin θ + sin ^ 2 θ ) dθ
0
θ= - 1/2 [ - 2 cos θ − 1/2 θ − 1/4 sin 2 θ ] | π
0
= - 1/2 [ - 2 (-1 ) + π / 2 - 1/4 ( 0 ) ] −
1/2 [ - 2 ( 1 ) + 1/2 ( 0 ) - 1/4 ( 0 ) ]
= 1/2 ( 2 + π / 2 ) - 1/2 ( - 2 )
= 1 + π / 4 + 1
= 2 + π / 4
= 2. 7853