The area element is the wedge dA =1/2r2dθ, so your integral is
integral from 0 to 2pi of (1-sin(θ))2dθ which leads to 3/4(θ) evaluated from 0 to 2pi
most of the integral cancels when you put in the bounds and you have to do the 1/2(1-cos(2θ)) sub for sin2(θ)
Good luck!