
Ralph W. answered 08/20/23
Real-World Problem Solving, Customized Learning. Unlock Your Potential
To process one file at a time in a DOS batch script, you can use a loop to iterate through the files in the folder and execute your desired tasks on each file. Here's a basic example of how you can achieve this:
```batch
@echo off
setlocal enabledelayedexpansion
set "sourceFolder=C:\Path\To\Source\Folder"
set "destinationFolder=C:\Path\To\Destination\Folder"
for %%F in ("%sourceFolder%\*.*") do (
set "currentFile=%%~nF%%~xF"
echo Processing: !currentFile!
rem Move the current file to the destination folder
move "%%F" "%destinationFolder%\!currentFile!"
rem Execute another batch file with the current file as an argument
call AnotherBatchFile.bat "!currentFile!"
)
endlocal
```
In this example:
1. Replace `"C:\Path\To\Source\Folder"` with the actual path of your source folder.
2. Replace `"C:\Path\To\Destination\Folder"` with the actual path of your destination folder.
3. The loop iterates through each file in the source folder using `for %%F in ("%sourceFolder%\*.*")`.
4. Inside the loop:
- `%%~nF` extracts the name of the current file (without extension).
- `%%~xF` extracts the extension of the current file.
- `!currentFile!` is a delayed-expanded variable holding the current file's name and extension.
- The `move` command moves the current file to the destination folder.
- The `call` command executes another batch file named `AnotherBatchFile.bat`, passing the current file as an argument.
Adjust the paths, file extensions, and tasks to match your requirements.
Note that this example processes files one by one and then moves them to the destination folder. After the loop completes, you can continue executing tasks in the `AnotherBatchFile.bat` script using the file passed as an argument.