C++: How to use command line arguments?

Question

I know that to use command line arguments, I have to do this.`int main(int argc, char* argv[])`Now most of the documentation i read about taking in command line arguments explain the situation, something like this:> Command-line arguments are given after the name of a program in> command-line operating systems like DOS or Linux, and are passed in to> the program from the operating system.So the only way i know to open my program, is to open it normally like i would do, either start debugging or open the exe fileNow here it seems that, to use command line arguments the program has to be opened differently, Using the Command-Line (DOS/Command Prompt for example), and then write the arguments after it.So my question isHow do i open my program using the Command-Line, and how do i enter the arguments after the program name?

Answer 1

You go to the file folder where the *.exe file lives using the change directory command...

> cd pathname

You can issue directory command to make sure it is there

> dir

Once found, you do

>ProgramName clpArg1 clpArg2 clpaArg3 ....

where clpArgx is any one of the command line parameter argument

For example, imagine an OLD word processor , whose executable filename is

wordproc.exe

Then the command

prompt:> wordproc filename.doc

will start the word processor, read the document and render it in the editor.

At that point, there are TWO copies of the document... 1 in the editor and the

other on the disk

===================================================

now on the source code side:

argc is the argument count, which is the number of arguments specified on the command line INCLUDING the program name.

argv is the array of string tokens given on the command line.

So for example:

prompt:> myprog one two three

argc=4

argv[0] = "myprog.exe"

argv[1] = "one"

argv[2]="two"

argv[3] = "three"