
Samantha P. answered 07/21/18
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You are given that initially, at t=0, the concentration is 5 pounds of sugar per 110 gallons of water or c(0)=5/110=1/22~.045 pounds of sugar per gallon of water. Since sugar is being added at a rate of 2 pounds per minute and water is being added at a rate of 25 gallons per minute, the concentration (pounds of sugar per gallon water) at some minute t, is c(t)=(1+2t)/(22+25t). The concentration after 14 minutes has passed, c(14)=29/372~.078 pounds of sugar per gallon. The concentration has increased.