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Question

36x^2tan(4x^3-5)dx

Answer 1

Let u = 4x³-5; then du = 12x²du and we may write this integral as

3∫tan u du.

 

From a Table of Integrals, ∫tan u du = -ln|cos u| + C₁

Therefore this integral = -3ln|cos (4x³-5)| + C