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36x^2tan(4x^3-5)dx

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By:

Kenneth S. answered • 05/31/18

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Let u = 4x³-5; then du = 12x²du and we may write this integral as

3∫tan u du.

From a Table of Integrals, ∫tan u du = -ln|cos u| + C₁

Therefore this integral = -3ln|cos (4x³-5)| + C

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