Inactive Tutor answered 01/20/13
Tutor
New to Wyzant
Let u = x^(1/2).
u^2 - 4u + 2 = 0
Completing the square gives,
(u-2)^2 = 2
u = 2+/-sqrt(2)
x = [2+/-sqrt(2)]^2
Answer: x = .34, 11.66
Erin T.
asked 01/19/13Find the real solutions of each equation. Use a calculation to express any solutions rounded to 2 decimal places.
Inactive Tutor answered 01/20/13
Let u = x^(1/2).
u^2 - 4u + 2 = 0
Completing the square gives,
(u-2)^2 = 2
u = 2+/-sqrt(2)
x = [2+/-sqrt(2)]^2
Answer: x = .34, 11.66
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