Fisnik D.

asked • 08/04/17

Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.  

explain plz

Kenneth S.

shouldn't you describe this situation (by naming the triangles) in corresponding vertex order ? We need to see the figure or to be able to create it.
Check your spelling of Geometry, also.
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08/04/17

1 Expert Answer

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Andy C. answered • 08/04/17

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From sheer experience, I was able to draw
the diagram.
 
As expected, one triangle lies inside triangle ABC.
THe shortest leg is BC. THe longest leg is AB.
 
Point U lies on AB and V lies on AC.
UV is perpendicular to AC.
 
The similar triangles are AUV and ABC
 
 

AU           AB
------ = ---------
AV            AC


20x + 108         20X + 381
---------       = ---------------
372                        589


(20x + 108)* 589 = (20X + 381)*372

11780 X + 63612 = 7440X + 141732

4340 X - 78120 = 0

4340 X = 78120

X = 78120/4340 = 18


CHECK:

AU = 20*18 + 108 = 360 + 108 = 468

AB = 741

468/372 = 741/589 are equal ratios
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