
Philip P. answered 05/05/14
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-8 < 2x-2 < 0
-6 < 2x < 2 [Added 2 to all parts of the inequality]
-3 < x < 1 [Divided all parts of the inequality by 2]
On the number line, the solution exists between, but not including, -3 and +1.
-4 -3 -2 -1 0 1 2 3 4 5
<--|---o==|==|==|==o---|---|---|---|--->
Place open circles at -3 and +1 to indicate that they are not part of the solution. Darken (I used == marks) the number line between the circles at -3 and +1. That is the solution.