
Parviz F. answered 04/15/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
Convert it to aX^2 + bX + c =0
X ( 2X +3) = 5 ( 2X +3 )
X ( 2X +3 ) - 5 ( 2X +3 ) =0
These are already factored So:
( 2 X+3 ) ( X-5 ) =0
2X +3 = 0 X = -3/2
X -5 = 0 X = 5