Solve this with steps please

Question

x+y+z=7

x-y+2z=7

5x+y+z=11

 

Answer 1

x+y+z = 7

x-y+2z = 7

5x+y+z = 11

 

Add the first two equations to get 2x+3z = 14

Add the second and third equations to get 6x+3z = 18

 

So, we have the system:  2x+3z = 14

                                    6x+3z = 18

 

Subtract 6x+3z = 18 from 2x+3z=14 to get -4x = -4   So, x = 1

 

Therefore, 2(1) + 3z = 14

                         3z = 12   So, z = 4

 

Since x+y+z = 7, x=1, and z=4, 1+y+4 = 7

 

So, y = 2

 

Solution:  x=1, y=2, z=4