A number is 5 times greater than another number.By adding 8 to each number,the first number becomes only 3 times greater than the second .what are the two no.?

Question

Algebraic eqations

Answer 1

Assign variables.

Let x = first number

Let y = 2nd number

 

A number is 5 times greater than another number:

1)  x = 5y

adding 8 to each number,the first number becomes only 3 times greater than the second:

2)  x+8 = 3(y+8)

 

We have 2 equations from the information given.

 

Since we know x = 5y, substitute that into equation 2 and solve for y

 

5y + 8 = 3(y+8)    distribute through the parenthesis

5y + 8 = 3y + 24   subtract 3y from both sides

2y + 8 = 24           subtract 8 from both sides

2y = 16                 divide both sides by 2

y = 8

 

x = 5y = 40

 

Your numbers are {8, 40}