Steve S. answered 03/07/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Find the limit of x^2*sin(1/x) as x approaches infinity.
-1 ≤ sin(1/x) ≤ 1 for all x
As x → +∞, sin(1/x) → sin(0+) → 0+
As x → –∞, sin(1/x) → sin(0–) → 0–
As x → ±∞, x^2 → +∞
So the sine function is going to contribute a sign to the result:
As x → +∞, x^2*sin(1/x) → +∞
As x → –∞, x^2*sin(1/x) → –∞
So the textbook was only considering x → +∞.
See http://www.wyzant.com/resources/files/264328/limit_x_squared_times_sine_of_one_over_x