Sun K.
asked 05/22/13Find the equation of the plane?
If the vector function r(t)=<t+2, 2t^2-t+1, 3+t-t^3> is at the point (2, 1, 3) tangent to the plane containing the vector function s(u)=<u^2+2, -u+1, 2u^2-u+3>, find the equation of the plane.
1 Expert Answer

Robert J. answered 05/23/13
Certified High School AP Calculus and Physics Teacher
The normal direction of the plane
= r'(0) X s(0)
= <1, -1, 1> X <2, 1, 3>
= <-4, -1, 3>
So, the equation of the plane is 4(x-2) + (y-1) - 3(z-3) = 0.
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Sun K.
How did you get 4(x-2)+(y-1)-3(z-3)=0?
05/24/13