Edward C. answered 04/21/15
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Caltech Grad for math tutoring: Algebra through Calculus
Let C = number of cell phones
Let T = number of tv's
Fewer than 20 disposables ==> C + T < 20
Cost equation: 99.9*T + 60.35*C ≤ 1500
He can't buy fewer than 0 of either so additional constraints are D ≥ 0 and T ≥ 0
You can pick out 3 combinations of C and T that satisfy these constraints. For example, if he bought 10 tv's that would cost him 999 which would leave 1500 - 999 = 501 for the cell phones so he could buy 8 cell phones for 482.8