04/26/13
How do I factor 77x^3=22y^2-33x-88?
Heres what I did:
77x^3=22y^2-33x-88
11(7x^3+2y^2-3x-8)
x(7x^3+2y)(-3x-8)
(7x^2+2y)(-3-8)
(7x^2=2y)(-11)
at this point, im pretty sure ive done something wrong, but i cant figure what! Please...
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