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-16=(x+3)^3(x^2)
I need help on solving this equation to find x.
Let f(x) be a polynomial function such that f(-2)=5, f'(-2)=0 and f"(-2)=3. The point (-2,5) is which of the following for the graph of f?
How do you figure out this problem. Which is the correct answer choice and why? a) relative maximum b) relative minimum c) intercept d) inflection point e) none of these
Let f(x) be a polynomial function such that f(4)= -1, f'(4)=2 and f"(4)=0. If x<4, then f"(x)<0 and if x>4, then f"(x)>0.
The point (4,-1) is which of the following for the graph of f? How do you figure out this problem. Which answer choice is right and why? a) relative maximum b) relative minimum c)...
Find all of the zeros of the polynomial function.
Can anyone show me how to work this with a caculator g(x)=x^3+4x^2-5x-20?
