why are the the x intercepts 0,-3 ??? I thought they should be -3,-3
y=3(x+3)squared (dont know how to put sq root in)
y=3(x+3)squared (dont know how to put sq root in)
graph y=2x+3 in coordinate plane
y= 25-(x/3)^2 graph 6 points growth or decay, faster linear or slower than linear
That is all the question says. we are working with slope intercept form and standard form and the lessons like that. I just dont get this
y = 2x + 8 I know it's going to be above the line and it is going to be dashed, but I don't know how to find the origin. Does it included the origin or does not include the origin?
how do i know what a slope is on a graph
will also need to plot second line (like in a scatter plot or line graph). The point is to show the baseline points all Then need to plot times of those days the kid did the behavior. how do i do...
finding the domain and range on a exponential and linear graph