Algebra 1 word problem about horses.
At a horse show, ribbons are given for first, second,third, and fourth places. There are 20 horses in the show. How many different arrangements of four winning horses are possible?
At a horse show, ribbons are given for first, second,third, and fourth places. There are 20 horses in the show. How many different arrangements of four winning horses are possible?
I need help with algebra.I dont get it.I guess i cut up in class alot
the -6 is smaller and above the u. the 2 is outside the parentheses and smaller.
I have tried to solve this for 20 minutes
y = x^2 -6x X 1 2 3 4 5 6
Please explain the process not just the answer. Thank you!
x^4 - x^3 + 8x - 8
Using a graph what is the solution to the eqation x^2 + 4x - 5 = 0?
i missed school because i was sick and missed how to do inequalities. I looked it up and it looks really confusing!!! Can you help!?!?!?!?
Another one is (6x-5 ) < (6/x) Do you solve for x on these the way that you would if it were an equal sign rather than <> signs?
simplify the expression
How do you solve this since there isn't a c? I need the vertex points (ie: (2,5)) I'm in the 8th grade (Algebra 1) and our teacher neglected to tell us how to do these.
A family of 5 (2 adults & 3 children) go to the movies and they pay $27.75. The group of 5 behind them (3 adults & 2 children) pay 32.25. Figure the cost per adult and per child. Show your work....
Solve |x| + 7 < 4. {x | x < -11 or x > -3} {x | -3 < x < 3} Ø
please only answer if it's free. i can't afford to hire a tutor. thank you for your time.
find the slope, if it exists, of the line containing the pair of points. (7,3) and (-8,3)
(-2, 1) y - 1/2x, -2y = -5x-12
I am doing homework and this is the equation: y= -x -4 along with graph to chart it on. We are working on integer linear equations and graphing on charts. If you could help, it would clear some things...
What is the system of equations for these two and how do you find it?: y=x-3 and y=2x-5 Also these two?: 2x+y=-1 and y=-3 Thank you!
Solve 2+2=y algabraically
