Inactive Tutor answered • 04/14/13
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(a^2b)^-1 (a^-2+b^-2)^-1
= 1/(a^2b) * 1/(1/a^2 + 1/b^2)
= b/(a^2+b^2), after multiplying the top and the bottom by (a^2 b^2).
Cherilyn A.
asked • 04/14/13integral exponents
simplify (a^2b)^-1 (a^-2+b^-2)^-1
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