Compute the work done by the force field F(x, y)=<2, x> where C is the portion of y=x^2 from (0, 0) to (1, 1).
Compute the work done?
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1 Answer
work
= ∫F(x,y) ⋅ dr
= ∫2dx + xdy
= ∫[0, 1] (2 + 2x^2)dx, since dy = 2xdx
= 8/3







Comments
But what's dx?
- Sun K. from Los Angeles, CA 3/18/2013But what's dx?
- Sun K. from Los Angeles, CA 3/18/2013dx is the component of dr in the x-direction.
- Robert J. 3/18/2013