How do you solve this equation?
3x^2-x+1=0
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1 Answer
Quadratic equation always works: [-b +/- √(b2 - 4ac)]/2a
[1 +/- √(1 - 4(3)(1))]/2(3) = [1 +/- √(-11)]/6 = [1 +/- 11i]/6
How do you solve this equation?
Quadratic equation always works: [-b +/- √(b2 - 4ac)]/2a
[1 +/- √(1 - 4(3)(1))]/2(3) = [1 +/- √(-11)]/6 = [1 +/- 11i]/6

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