two fishing boats leave the harbor at the same time and using the same float plan. one average 17 knots (nautical miles per hour), and the other average 14.5 knots. how long will it take for the boats to be 10 nautical miles apart?
Let t = the time it takes the boats to be 10 nautical miles apart. Since rate x time = distance, the first boat's distance would be 17x and the second boat's distance would be 14x.
Since the first boat would be 10 nautical miles further, then we can express the relationship as
14x + 10 = 17x
Combining like terms, we get
10 = 3x
x = 10/3 hours or 3 1/3 hours