The interval described in set-builder notation by the inequality |3x-6|<18 has interval notation (a,b) for a = _ and b=_.
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Let us solve for the inequality:
3x-6 < 18
3x < 24
x < 8
3x-6 > -18
3x > -12
x > -4
So our final answer is -4 < x < 8 which translates to ]-4,8[