Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 4.00 MJ of energy (in the form of heat) if the temperature of the sodium is not to increase by more than 10.0 °C? Use CP = 30.8 J/(K·mol) for Na(l) at 500 K.

I understand that m= q/Cp(deltaT)

q= 4.00x 10^6 J

m=?

Cp= 30.8 J/k*mol

deltaT=10.0 degrees Celcius (also Kelvin)