If theta is in standard position and 0 </=theta</=2pi, determine the value of tan theta, if sin theta =3/5
If theta is in standard position and 0 </=theta</=2pi, determine the value of tan theta, if sin theta =3/5
Determine the solution(s) to the equation root3tantheta + 3 = 1 where 0</=theta</=2pi.
Solve for x, where 0</=x</=2pi (T) a. ((1+sinx)/(cosx))+((cosx)/(1+sinx))=4 b. sinxtanx+tanx+cosx = 0
Is sin2xsinx-cosx = -(3root3)/2 true for 7pi/6? Explain. Here is what I got: sin(2(7pi/6)) = root3 / 2 (0.86602540378) sin(7pi/6) = -1/2 (-.5) cos(7pi/6)...
cos x(2sinx + sqr root 3)(-sqr root 2 cosx + 1) = 0