Search 80,706 tutors

## Alix B.'s Resources

Hi, Sara. Bomb calorimetry calculations are a little different than solution calorimetry calculations. Instead of using Q=m*C*deltaT, you will use Q=C*deltaT where C is the heat capacity of the calorimeter. Note that your heat capacity of 23.3 has units of kj/degree C. This means that all we need...

Hi, Madison.     The equation we need to use is 1/Tolder+ 1/Tyounger= 1/Ttotal   We can plug in 3 for Ttotal (the total amount of time for both to change the oil) and 12 for Tolder (the time it takes the older brother to change the oil).  We get:    1/12...

Almost no one likes homework, especially mind-numbing drill and practice.  Problem after problem, over and over again... does this really accomplish anything?  The answer, according to the literature, is "yes!"     As a tutor, I recommend the website ixl.com to all primary and secondary students as the best way to practice math, but is it the best way?  To... read more

Hi, Aczuan.     To answer that question, we need to think of two perfect squares that are close to 86.  I like to use a "trial and error" strategy.  Let's see... 52 is 25... nope, way too small. Let's try 72=49.  Still way too small.  How about 92=...

Hi, Samantha.     An equation that will help with several of your questions is Q = mCΔT.  That is, heat (Q) equals mass (m) times specific heat capacity (C) times the change in temperature (ΔT).     You can plug in 85 for Q, 18 for m, 0.128 for C and leave ΔT...

Hi, Annna.     Let me do a similar problem for you.  You can follow along with my work and solve your problem.     Let's say I wanted to find a polynomial with roots 6, 8, and the square root of 7.  First, I would start by recognizing that that if the...

Hi, Davis.     You can translate the first sentence into an equation by using "w" and "L" for width and length, respectively.  Note that the word "is" means an equals sign in "math language".  Also, the phrase "7 inches less"...

Hi, Cynthia.     I would start by combining like terms on both sides of the equation so that it becomes   2x+4= 4x-10   Next, I would subtract 2x from both sides to get   4=2x-10   I would then add 10 to both sides, resulting...

Hi, Norma.  Do the instructions for the problem say something like "expand," "simplify," "multiply," or "write in standard form"?  If so, what you need to do is use the FOIL technique.  FOIL is an acronym for "first, outside, inside, last"...

Greetings, scholars!     Last semester, I took the initiative to refresh my knowledge of physics by taking Physics I for Physical Science Majors from the University of Colorado Boulder via Coursera.  Learning physics- even re-learning physics!- can be a formidable challenge.  Making the connection between the real world and the symbols on the page isn't always easy... read more

Greetings, scholars! Usually I reserve my blog for sharing tech tips and practical advice, but the upcoming holiday has me reflecting on how thankful I am for the wonderful teachers I have had over the years. There's Dr. Galvin, who taught me how to think about discrete mathematics, helped me appreciate "vintage" math literature, and showed me the online encyclopedia of integer... read more

Greetings, scholars!     Using flashcards is a tried-and-true method for rote memorization.  As a student, I had stacks of index cards with terms on one side and definitions on the other.  These cards proved the key to success in subjects like biology and psychology.  Flashcards also help in subjects like calculus and chemistry, although memorization is not a substitute... read more

Not sure if this counts as a simple way to find the two terms, but you could solve a system of equations, i.e.  A+B = 99 A*B= -3870 Solve the system by substitution.  I would prefer this method over trial and error.

Greetings, scholars! One of my dad's favorite sayings is, "If something seems too good to be true, it probably is." The website Coursera is an example of why that saying needs the word "probably". The idea of taking real college courses from top-notch instructors at prestigious schools for free sounds impossible, yet students around the world are doing just that. When... read more

Greetings, scholars! The first step to success in any endeavor is having the right tools. Keeping tools organized and handy is equally important, but the overwhelming amount of information in most classes causes even the most powerful tools to get lost in the cluttered garage of facts, formulas, and applications. What we need as mathematical scholars is a neat, uncluttered toolbox where... read more