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Herb K.'s Resources

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average value of a function, f(x), over an interval [a,b], is given by (1/(b - a))[integral from a to b of f(x)dx], which in this case, a=0 and b=6, becomes [1/(6 - 0)]S(0,6)x^2 dx = (1/6)[x^3/3](0,6) = (1/18)[6^3 - 0^3] = (1/18)(6)(36) = 36/3 = 12

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Consider: 4(30) = 120 then, consider various ways to multiply two numbers together to get 120: 1       120           note:  1 + 120 = 121 2         60          ...

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(x+3)(x^2+4x-5) (answer)

if you are being asked to multiply, then use Distributive Property:  (x + 3)(x^2 + 4x - 5) = x(x^2) + x(4x) + x(-5) + 3x^2 + 3(4x) + 3(-5) = x^3 + 4x^2 - 5x + 3x^2 + 12x - 15 = x^3 + 7x^2 + 7x - 15   if, on the...