average value of a function, f(x), over an interval [a,b], is given by (1/(b - a))[integral from a to b of f(x)dx], which in this case, a=0 and b=6, becomes [1/(6 - 0)]S(0,6)x^2 dx = (1/6)[x^3/3](0,6) = (1/18)[6^3 - 0^3] = (1/18)(6)(36) = 36/3 = 12
average value of a function, f(x), over an interval [a,b], is given by (1/(b - a))[integral from a to b of f(x)dx], which in this case, a=0 and b=6, becomes [1/(6 - 0)]S(0,6)x^2 dx = (1/6)[x^3/3](0,6) = (1/18)[6^3 - 0^3] = (1/18)(6)(36) = 36/3 = 12
write the line 3x + 4y = 10 in slope-intercept form: y = -(3/4)x + (5/2) = mx + b, so that m = -(3/4); next, consider the line, y = Mx + B, passing through (-1,-3), perpendicular to the line 3x + 4y = 10, intersecting that line at (c,d); since the line...
Consider: 4(30) = 120 then, consider various ways to multiply two numbers together to get 120: 1 120 note: 1 + 120 = 121 2 60 ...
if you are being asked to multiply, then use Distributive Property: (x + 3)(x^2 + 4x - 5) = x(x^2) + x(4x) + x(-5) + 3x^2 + 3(4x) + 3(-5) = x^3 + 4x^2 - 5x + 3x^2 + 12x - 15 = x^3 + 7x^2 + 7x - 15 if, on the...
just as log(100) = 2, because 10^2 = 100 (10 being the base of the COMMON log), so also we have 10^k = 7