Turn the word problem into an equation. Call the unknown number x. The square of that number is x2. The square of 5 more than that number is (x+5)2. The sum of those two quantities, x2 + (x+5)2, equals 157. OK, let's solve it. x2 + (x+5)2...
Turn the word problem into an equation. Call the unknown number x. The square of that number is x2. The square of 5 more than that number is (x+5)2. The sum of those two quantities, x2 + (x+5)2, equals 157. OK, let's solve it. x2 + (x+5)2...
Christina, you have two variables, x and y, but only one equation. You cannot solve for both x and y unless you have a second equation. You can simplify the equation that you have, a bit: x - 4y = 17 - 3x + 12y (combine the constants) x = 17 - 3x + 16y (add...
Any number between 6 1/2 and 7 1/2 rounds to 7. Also, 6 1/2 itself rounds to 7.