sin^2x-cos^2x=2sin^2x-1 (tanx+cotx)/tanx=csc^2x

sin^2x-cos^2x=2sin^2x-1 (tanx+cotx)/tanx=csc^2x

I'm having trouble trying to prove this trig identity. Help is greatly appreciated. Thanks in advance. 1/(csc-cot) = (1+cos)/sin

Use the trigonometric identities to write each expression in terms of a single trigonometric function. A. Sin^2 D. (tan^2 +1)Sin^2 Cos^2 B. cot +1 E. 1+ 1 tan +1 cot^2 C. Sin^2 +cos^2...

help please

Please help

help please

I am very confused as to what identity I need to use to simplify this equation.

When verifying trigonometric identities, can you multiply both sides by a number to make it easier to solve?

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I have a math problem in which I have to prove the identity sin2θ= 2tanθ/1+tan2θ using Double-Angle Identities and I'm trying to figure out how to solve it.

to prove: (tan(x)+sec(x)-1)/(tan(x)-sec(x)+1)=sec(x)+tan(x)

Solve the given equation over the interval [0,2): 2sinx+ (sqrt 3) sin^2x=-(sqrt 3) cos^2x A. x=0, and x=(pi/2), and x=(3 pi/2), and x=2(pi)x=(3 pi/2), and x=(7 pi/2) b. x=(4 pi/3) and...

Provide an exact evaluation of the expression: tan (-285°).

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