point (5,-19) y-intercept is 1

point (5,-19) y-intercept is 1

A. 2x2y2 + 3x4y + 10x6 B. 4x4y2 + 6x3y5 + 10x C. -3x8y2 + 9x2y + 10x2 D. -7x6y2 + x3y8 + 10x2

this is for algebra 1 and I don't understand how to work it

I need to put the pair of points (-6,2) and (1,-8) into standard form, but i am struggling and I don't know how to do it

Write the standard form of the equation of the line through the given points

Write the standard form of the equation of the line through the given points

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X=(3,5) passes through point -3,-36

Line m passes through C(-2,0) and D(1,-3). Write the equation of line m in standard form.

Write the equation of the line passing through the given points. Write the equation in standard form Ax+By=C. (-4,-2) and (-6,-1)

8 + 3x = -9y

Use the two points to write a slope-intercept equation. Then, transform it into Standard Form. (1,4) and (-5,-9)

Write Standard Form for a line with the points (1,4) and (3,9)

Write Standard-Form for a line with the slope of 5 and the point (2,5)

How many passengers did the train carry in the year?Answer in standard form.

the answer choices I have are A. 3x-4y=12 B. 3x+4y=12 12x-4y=-3 12x+4y=-3

Write the standard form of the equation of the line through the given point with the slope through: (-2,5) , slope = -4 .

I am just curious which one would be the preferable option when graphing a parabola

Use the information given to write an equation in standard form

I am trying to rewrite x-9y=3 in standard form

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