Need to prove that <a>C(a) ≤ G where <a>C(a) = {bc|b∈<a>, c∈C(a)}

Need to prove that <a>C(a) ≤ G where <a>C(a) = {bc|b∈<a>, c∈C(a)}

prove Cos x cot x _____ - ______ = cos 2 x _ cot 2 x sec x tan...

Prove x/y + y/x ≥ 2. Now the book gives (x-y)2 ≥0 and from there derived the above, hence proving it. I understand that, because you start at a known fact and end up at the thing...

Given: Triangle ABD is an equilateral triangle and E is the midpoint of segment AD. Prove: Segment EB bisects angle DBA. Prove: Segment EB is perpendicular to Segment...

Prove: Triangle ABF is congruent to Triangle EHG Given: angle H = angle B and segments FG = EA, angles HEG and FAB are right angles,

~ mean not ^ mean and ∨ mean or Help me pls

Can anyone help me solving this problem, Im really really lost. Thank you

How to do this, please help me. Thank you very much!

I didnt understand Let say X = 2a +1 while y = 2b+1 Why you need to multiply xy rather x+y, as you can see below: XY = (2a+1)(2y+1) <- correct X+Y...

Need help with this geometryproof please help.

A is the midpoint of PQ, B is the midpoint of PA, and C is the midpoint of PB

Proof for the equation that x+y=2xy using whatever method.

I do know how to solve this problem. Can you show the steps in solving it. What do i substitute for a and b

Case proof

x,y,z ∈ ℝ3 and x+y+3z=0 How do I prove ax+by+cz=dx+ey, if d and e are real numbers chosen to fit the equation? Thank you very much if...

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Given rhombus ABCD. We draw the diagonal BD and the angular bisector of BK of <ABD. Proof that m<AKB = 3 m<ABK.

Given: Segment AB is parallel to segment CD Prove: Arc of mAC = arc of mBD Please help!

If all the primes where (2,3,5) then you can multiply them together to get 30, but then you add 1. Like how 64 is made up of 2x2x2x2x2x2, which can't this new number be made up of multiple smaller...

It can't be in a graph and has to be in the statement-reason format. I'll need the equations used as well

Given p is parallel to q, if line AD is parallel to line BE and line CF is parallel to line BE, then angle BAC is congruent to angle EDF?

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