A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. For the half life: The half...
A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. For the half life: The half...
A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. For the half life: The half...
The variable Z is directly proportional to X, and inversely proportional to Y. When X is 3 and Y is 14, Z has the value 3.8571428571429. What is the value of Z when X = 12, and...
solve over the interval 0 degrees and 360 degrees
Find the value of k such that the system of linear equations is inconsistent. 6x + 2y = 8 −9x + ky = −11 k=?
Having trouble with 2 questions can you walk me through both? do you just square the radicals? solve √4x-2 = √2x+6 and... √2x-1...
solve (2x+3)/(x+5) + (1)/(2) = (7)/(2x+10)
solve √2x-1 +2 = √x+2 +3 thanks
put into quadratic formula and put the answers at the bottom but let me do the work please 4x2-3x+3=0 Forgot what to do when x2 is greater than 1 Thanks...
simplify n+3)/(n2-5n+6) + (6)/(n2-7n+12)
Solve √4x-2 = √2x+6 Thanks
1/x+3 + 1/x+4 is less than or equal to 0 Picture of the problem http://i.imgur.com/pvojkPT.png Edit: The answer is (-infinity, -4) U [-7/2,...
If the rational function y = r(x) has the vertical asymptote x = 2, then as x → 2+, either y → *insert number here* or y → *insert number here* What does this...
From f(x) = 4x − 3, g(x) = 2 − x (a) (f + g)(x) = (b) (f − g)(x) = (c) (fg)(x) = (d) (f/g)(x) = And What...
f(x) = x + 8 1. f(x2) = 2. (f(x))2 =
How was that answer gotten? √20 = + - 2√5
Simplify 1) (3)/(m) - (3)/(2m+3) / (3)/(m2) + (1)/(2m+3)
2 equations That are giving me difficulty. Solve a) (2x+3)/(x+5) + (1)/(2) = (7)/(2x+10) b)(x2+4x+3)/(x2+5x+6)...
Scenario with formulas: Cost Function C(Q)= 8q+3200 Revenue Function R(Q)= -10p^2+850p ( in terms of q, (1/10q^2)+85q ...? I think?) Find the break...
Needing some help with this problem