Use of Graphing Calculator for pH Box Math
[H+] = 2.75 E-6
Start with [H+] = 2.75 E-6.
Input (-) (This is the ‘change sign’ button.), log (not
ln, the natural log) 2 . 7 5 E
(-) 6 and enter. The pH will be displayed as 5.560667306.
It is dreadfully unrealistic to consider that number as a final answer of the
pH of the solution because pH is not generally accurately measurable beyond
two places to the right of the decimal. If this were a
final answer, I would round it to 5.56, but if you want to continue around
the pH box, you should keep as many of the digits as you can.
pH = 5.560667306
Punch (-) to change the sign and ans to call up the previous
answer. (This inserts the 5.60667306 into the new calculation.) Punch +,
the plus sign and 1 4enter to add 14 to the negative pH.
This will give you the pOH of 8.439332694. (Round to 8.44 if this is your final
pOH = 8.439332694
To get to the [OH–]
from the pOH, punch in the antilog (usually INV or shift and log),
change sign (-), and the pOH from the previous answer ans
[OH–] = 3.636363636 E-9
To get back to the [H+]
from the [OH–],
enter the Kw, 1 E -14, and divide by the previous answer. Punch 1
E (-) 1 4 ÃƒÂ· ans enter
[H+] = 2.75 E-6
Now for practice, go around the pH box the other way.
The rules are:
- To get pH from [H+]
or to get pOH from [OH–], use the negative log.
- To go from [OH–] to pOH or from
[H+] to pH, use antilog of the negative number.
- To go from [H+]
to [OH–] or back, first put in the Kw, 1E-14 and divide by the one
you are leaving.
- To go from pH to pOH or back, subtract the number
you have from 14.
Proficiency in pH box calculations requires practice. There
is no Wyzant quiz on the pH box because you can make your own exercises,
but you will use the calculations in many problems in this acid-base section.