# Arithmetic Progression

A progression is another term for sequence. Therefore, Arithmetic Progressions (also known as Arithmetic Sequences) are special sequences defined by the property that the difference between any two consecutive terms of the sequence are constant. Whereas the rule for regular sequences is that the difference between consecutive terms has to have some kind of relationship, it may or may not be constant. The relationship may not even be of a 'difference' nature but may be of a 'multiplicative' nature. This is not so for Arithmetic sequences, the relationship has to be of a difference nature only. This common difference is denoted by the letter d.

As an example, take a look at the sequence below; for the sequence below to be an arithmetic progression, the difference between consecutive terms has to be some constant d such that:    since that relationship must hold true, we can move further and say that    the same applies to a4   the same also applies to the last term an where byan-1 is the second last term So now let us take a replace the terms in the sequence with their corresponding terms that we have obtained From the above new sequence, we should observe that to get the next term, you always add the first term to the product of the common difference and one less than the position of the next term.

i.e. if the next term is denoted by the letter n, then The above relationship should always hold true as the relationship between consecutive terms in an arithmetic progression. You can check that it is true by substituting for the values of the sequence we've been working with.

This is what makes arithmetic progressions such special sequences, all you need to know is the first term and the common difference d and then you'll be able to find any term in the sequence without having to find its preceding term.

For example, given that the common difference in an arithmetic progression is 5 and the first term is 3, find the 10th and 25th terms of the sequence.

solution:

The common relationship between all terms in an arithmetic progression is given by      ## Arithmetic Series

Since there exist Arithmetic Sequences, Arithmetic Series also exist and are the sums of the terms in arithmetic sequences.

We have already seen that a series is given in the following form where Sn is the notation for the sum of a series.

We have also established that the above terms can also be written in terms of the first term and the common difference but the above can also be written in terms of the last term as follows If we were to add the two sums we would obtain the following  The above is obtained after some tedious addition and collecting like terms but it turns out as a nice simple expression

So we now have an expression for the sum in terms of only the first and last terms as but we can simplify this further since we already established a way of expressing the any term in terms of the first term and the common difference d  so now we have two options of formula to use to find the sum of an arithmetic progression.

Remembering from the section on Series, the notation for summation: ## Examples of Arithmetic Progression

### Example 1

Find the sum of the Arithmetic Progression below given that the total number of terms is 15 Step 1

Since we haven't been told what the common difference \textbf{d} is, we need to find that first Step 2

Next to find the sum, all we have to do is substitute in the formula since we already have the first and last terms Step 3 Step 4   ### Example 2

Given that the following is an Arithmetic Progression with 20 terms, find its sum Step 1

Like in the previous example, we're not given the common difference, and in this case we don't even have the last term. We could choose to find both or we could just find the difference and use only this and the first term to find the sum. Step 2

The formula below only utilizes the first term and the common difference Step 3

Substituting: Step 4  ## Quiz on Arithmetic Progression

1. How many gifts do you receive in total in the song "Twelve Days of Christmas"?

The first step is to list out the sequence for the 12 days:

• On the first day, you receive 1 gift
• On the second day you receive 1 + 2 = 3 gifts
• On the third day you receive 1 + 2 + 3 = 6
• On the fourth day you receive 1 + 2 + 3 + 4 = 6
• And so on, until you reach day 12

The sequence for the gifts received on each day becomes: To find the total number of gifts, just change the sequence into a series and find its sum  364

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